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Two sum #1226
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// https://leetcode.com/problems/two-sum/ | ||
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// Given an array of integers, return indices of the two numbers such that they add up to | ||
// a specific target. | ||
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// You may assume that each input would have exactly one solution, and you may not use the | ||
// same element twice. | ||
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// Example: | ||
// Given nums = [2, 7, 11, 15], target = 9, | ||
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// Because nums[0] + nums[1] = 2 + 7 = 9, | ||
// return [0, 1]. | ||
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const TwoSum = (nums, target) => { | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. That's a pretty naive implementation with a runtime of O(n²). Please document this in the JSDoc comment. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Please see the docs and use the proper |
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for (let i = 0; i < nums.length; i++) { | ||
for (let j = i + 1; j < nums.length; j++) { | ||
if (nums[i] + nums[j] === target) { | ||
return [i, j] | ||
} | ||
} | ||
} | ||
} | ||
export { TwoSum } |
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import { TwoSum } from '../TwoSum' | ||
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describe('TwoSum tests', () => { | ||
it('check that a variety of inputs return the correct answer', () => { | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Just use |
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expect(TwoSum([2, 7, 11, 15], 9)).toEqual([0, 1]) | ||
expect(TwoSum([2, 7, 11, 15, 6], 8)).toEqual([0, 4]) | ||
expect(TwoSum([1, 0, 5, 7, 3, 4], 6)).toEqual([0, 2]) | ||
expect(TwoSum([0, 8, 3, 1, 2, 7, 3], 6)).toEqual([2, 6]) | ||
expect(TwoSum([0, 5, 4, 2, 6, 7, 9, 1], 3)).toEqual([3, 7]) | ||
}) | ||
}) |
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Can you try to use a JSDoc comment right above the definition of
TwoSum
?