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Hello everyone,

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Thank you for being part of this journey. Here's to today and all the wonderful possibilities it brings!

Leetcode Daily Challenge Solutions

This is my attempt to make the coding experience easier for you guys so that you can easily learn what to do in today's leetcode challenge.

Always here to assist you guys.

Today's 04-04-24 Problem Link

1614. Maximum Nesting Depth of the Parentheses

Intuition

• I aim to find the maximum depth of nested parentheses in a given string.

Approach

• I initialized two variables, jawab and khula, to keep track of the maximum depth and current depth, respectively.
• Iterated through each character c in the string s.
• If c is an opening parenthesis '(', incremented khula and update jawab to the maximum of its current value and khula.
• If c is a closing parenthesis ')', decremented khula.
• Finally, returned jawab as the maximum depth of parentheses.

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Have a look at the code , still have any confusion then please let me know in the comments Keep Solving.:)

Complexity

• Time complexity : $O(n)$

$n$ : length of the given string

• Space complexity : $O(1)$

Code

class Solution {
  public int maxDepth(String s) {
    
        // Initialize variables
        int jawab = 0; // Store the maximum depth found so far
        int khula = 0; // Keep track of the current depth

        // Iterate through each character in the string
        for (final char c : s.toCharArray()){
            // If the character is an opening parenthesis
            if (c == '('){
                khula++; // Incrementing the current depth
                jawab = Math.max(jawab, khula); // Updating maximum depth if necessary
            }
            // If the character is a closing parenthesis
            else if (c == ')'){
                khula--; // Decrementing the current depth
            }
        }
        // Returning the maximum depth found
        return jawab;
    }
}