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+ /***************************************************************************************
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+ * *
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+ * CODERBYTE BEGINNER CHALLENGE *
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+ * *
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+ * First Factorial *
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+ * Using the JavaScript language, have the function CheckNums(num1,num2) take both *
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+ * parameters being passed and return the string true if num2 is greater than num1, *
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+ * otherwise return the string false. If the parameter values are equal to each other *
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+ * then return the string -1 *
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+ * *
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+ * SOLUTION *
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+ * This solution has to use an If...else if...else statement since you will be *
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+ * comparing for three different comparisons.
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+ * *
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+ * Steps for solution *
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+ * 1) If num1 and num2 are equal then return string -1 *
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+ * 2) Else If num2 is greater than num1 then return true *
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+ * 3) Else return false *
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+ * *
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+ ***************************************************************************************/
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+
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+ function CheckNums(num1,num2) {
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+
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+ if (num1 === num2) {
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+ return "-1";
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+ } else if (num2 > num1) {
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+ return true;
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+ } else {
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+ return false;
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+ }
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+
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+ }
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