/***************************************************************************************

* *

* CODERBYTE BEGINNER CHALLENGE *

* *

* Powers of Two *

* Using the JavaScript language, have the function PowersofTwo(num) take the num *

* parameter being passed which will be an integer and return the string true if *

* it's a power of two. If it's not return the string false. For example if the *

* input is 16 then your program should return the string true but if the input is *

* 22 then the output should be the string false *

* *

* SOLUTION *

* To find if a number is a power of 2 you divide number by 2 repeatedly. *

* If final number is a two then it is a power of 2. I will use a while loop to *

* handle the repeated division by two. I will use modulus to determine if final *

* number is two meaning we have a number that is a power of 2. *

* *

* Steps for solution *

* 1) Initialize vars divis and newNum *

* 2) Loop by dividing number by 2 and seeing if it is an even number *

* 3) Test if last number is 2 meaning it is a power of 2 *

* *

***************************************************************************************/

function PowersofTwo(num) {

var divis;

var newNum;

divis = num % 2;

newNum = num / 2;

while ( divis === 0 && newNum !== 2) {

divis = newNum % 2;

newNum = newNum / 2;

}

if (newNum === 2) {

return true;

}

else {

return false;

}

}