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README.md

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@@ -923,6 +923,7 @@ _If you like this project, please leave me a star._ ★
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| # | Title | Solutions | Video | Difficulty | Tag
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|-----|----------------|---------------|---------------|---------------|-------------
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|1378|[Replace Employee ID With The Unique Identifier](https://leetcode.com/problems/replace-employee-id-with-the-unique-identifier/)|[Solution](../master/database/_1378.sql) || Easy |
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|1369|[Get the Second Most Recent Activity](https://leetcode.com/problems/get-the-second-most-recent-activity/)|[Solution](../master/database/_1369.sql) || Hard |
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|1364|[Number of Trusted Contacts of a Customer](https://leetcode.com/problems/number-of-trusted-contacts-of-a-customer/)|[Solution](../master/database/_1364.sql) || Medium |
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|1355|[Activity Participants](https://leetcode.com/problems/activity-participants/)|[Solution](../master/database/_1355.sql) || Medium |

database/_1378.sql

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--1378. Replace Employee ID With The Unique Identifier
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--
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--Table: Employees
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--
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--+---------------+---------+
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--| Column Name | Type |
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--+---------------+---------+
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--| id | int |
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--| name | varchar |
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--+---------------+---------+
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--id is the primary key for this table.
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--Each row of this table contains the id and the name of an employee in a company.
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--
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--
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--Table: EmployeeUNI
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--
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--+---------------+---------+
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--| Column Name | Type |
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--+---------------+---------+
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--| id | int |
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--| unique_id | int |
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--+---------------+---------+
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--(id, unique_id) is the primary key for this table.
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--Each row of this table contains the id and the corresponding unique id of an employee in the company.
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--
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--
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--Write an SQL query to show the unique ID of each user, If a user doesn't have a unique ID replace just show null.
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--
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--Return the result table in any order.
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--
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--The query result format is in the following example:
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--
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--Employees table:
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--+----+----------+
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--| id | name |
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--+----+----------+
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--| 1 | Alice |
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--| 7 | Bob |
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--| 11 | Meir |
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--| 90 | Winston |
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--| 3 | Jonathan |
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--+----+----------+
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--
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--EmployeeUNI table:
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--+----+-----------+
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--| id | unique_id |
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--+----+-----------+
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--| 3 | 1 |
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--| 11 | 2 |
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--| 90 | 3 |
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--+----+-----------+
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--
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--EmployeeUNI table:
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--+-----------+----------+
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--| unique_id | name |
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--+-----------+----------+
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--| null | Alice |
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--| null | Bob |
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--| 2 | Meir |
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--| 3 | Winston |
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--| 1 | Jonathan |
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--+-----------+----------+
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--
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--Alice and Bob don't have a unique ID, We will show null instead.
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--The unique ID of Meir is 2.
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--The unique ID of Winston is 3.
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--The unique ID of Jonathan is 1.
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--
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--# Write your MySQL query statement below
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select uni.unique_id, emp.name from Employees emp
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left join
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EmployeeUNI uni
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on emp.id = uni.id

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