task: #1873

Ivanbyone · Ivanbyone · commit d04480fe8852 · 2025-07-11T15:40:57.000+03:00
diff --git a/README.md b/README.md
@@ -146,6 +146,7 @@ Useful for preparing for technical interviews and improving your SQL skills.
     - [1741. Find Total Time Spent by Each Employee](./leetcode/easy/1741.%20Find%20Total%20Time%20Spent%20by%20Each%20Employee.sql)
     - [1789. Primary Department for Each Employee](./leetcode/easy/1789.%20Primary%20Department%20for%20Each%20Employee.sql)
     - [1795. Rearrange Products Table](./leetcode/easy/1795.%20Rearrange%20Products%20Table.sql)
+    - [1873. Calculate Special Bonus](./leetcode/easy/1873.%20Calculate%20Special%20Bonus.sql)
     - [1890. The Latest Login in 2020](./leetcode/easy/1890.%20The%20Latest%20Login%20in%202020.sql)
     - [1965. Employees With Missing Information](./leetcode/easy/1965.%20Employees%20With%20Missing%20Information.sql)
     - [1978. Employees Whose Manager Left the Company](./leetcode/easy/1978.%20Employees%20Whose%20Manager%20Left%20the%20Company.sql)
diff --git a/leetcode/easy/1873. Calculate Special Bonus.sql b/leetcode/easy/1873. Calculate Special Bonus.sql
@@ -0,0 +1,31 @@
+/*
+Question 1873. Calculate Special Bonus
+Link: https://leetcode.com/problems/calculate-special-bonus/description/?envType=problem-list-v2&envId=database
+
+Table: Employees
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| employee_id | int     |
+| name        | varchar |
+| salary      | int     |
++-------------+---------+
+employee_id is the primary key (column with unique values) for this table.
+Each row of this table indicates the employee ID, employee name, and salary.
+ 
+
+Write a solution to calculate the bonus of each employee. The bonus of an employee is 100% of their salary if the ID of the employee is an odd number and the employee's name does not start with the character 'M'. The bonus of an employee is 0 otherwise.
+
+Return the result table ordered by employee_id.
+*/
+
+SELECT
+    employee_id,
+    (CASE
+        WHEN employee_id % 2 = 0 OR LEFT(name, 1) = 'M' 
+            THEN 0
+        ELSE salary
+    END) AS bonus
+FROM Employees
+ORDER BY employee_id ASC
