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1. Add leetcode solutions with tag amazon.
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leetcode/239. Sliding Window Maximum.md

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}
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}
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```
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### Amazon Session
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* Method 1: Deque
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```Java
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class Solution {
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public int[] maxSlidingWindow(int[] nums, int k) {
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if(nums.length < k || nums.length == 0) return new int[0];
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int[] result = new int[nums.length - k + 1];
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Deque<Integer> deque = new ArrayDeque<>();
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int i = 0, index = 0;
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for(i = 0; i < nums.length; i++){
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if(i - k >= 0 && !deque.isEmpty() && deque.peek() == i - k) deque.pollFirst();
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int add = nums[i];
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while(!deque.isEmpty() && add >= nums[deque.getLast()]){
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deque.pollLast();
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}
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deque.addLast(i);
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if(i - k + 1 >= 0) result[index++] = nums[deque.getFirst()];
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}
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return result;
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}
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}
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```

leetcode/413. Arithmetic Slices.md

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### 413. Arithmetic Slices
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### Question
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A sequence of number is called arithmetic if it consists of at least three elements and if the difference between any two consecutive elements is the same.
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For example, these are arithmetic sequence:
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1, 3, 5, 7, 9
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7, 7, 7, 7
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3, -1, -5, -9
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The following sequence is not arithmetic.
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1, 1, 2, 5, 7
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A zero-indexed array A consisting of N numbers is given. A slice of that array is any pair of integers (P, Q) such that 0 <= P < Q < N.
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A slice (P, Q) of array A is called arithmetic if the sequence:
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A[P], A[p + 1], ..., A[Q - 1], A[Q] is arithmetic. In particular, this means that P + 1 < Q.
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The function should return the number of arithmetic slices in the array A.
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```
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Example:
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A = [1, 2, 3, 4]
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return: 3, for 3 arithmetic slices in A: [1, 2, 3], [2, 3, 4] and [1, 2, 3, 4] itself.
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```
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### Solution
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* Method 1: Find number at end of each fast.
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```Java
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class Solution {
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public int numberOfArithmeticSlices(int[] A) {
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if(A == null || A.length < 3) return 0;
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int res = 0;
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int slow = 0, fast = 1;
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int diff = A[fast] - A[slow];
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fast++; // fast = 2 now.
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for(; fast < A.length; fast++){
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if(A[fast] - A[fast - 1] == diff){
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if(fast - slow + 1 >= 3){
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res += fast - 2 - slow + 1;
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}
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continue;
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}else{ // diff changes
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slow = fast - 1;
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diff = A[fast] - A[fast - 1];
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}
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}
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return res;
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}
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}
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```

leetcode/74. Search a 2D Matrix.md

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}
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}
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```
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### Amazon session
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* Method 1: search
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```Java
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class Solution {
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public boolean searchMatrix(int[][] matrix, int target) {
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if(matrix == null || matrix.length == 0 || matrix[0].length == 0) return false;
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int height = matrix.length, width = matrix[0].length;
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int x = 0, y = width - 1;
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while(x >= 0 && x < height && y >= 0 && y < width){
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if(matrix[x][y] == target) return true;
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else if(matrix[x][y] < target){
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x++;
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}else{
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y--;
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}
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}
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return false;
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}
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}
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```

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