Add solution #1694

JoshCrozier · JoshCrozier · commit 7e51cfe50ceb · 2025-04-26T12:50:01.000-05:00
diff --git a/README.md b/README.md
@@ -1,4 +1,4 @@
-# 1,479 LeetCode solutions in JavaScript
+# 1,480 LeetCode solutions in JavaScript
 
 [https://leetcodejavascript.com](https://leetcodejavascript.com)
 
@@ -1304,6 +1304,7 @@
 1689|[Partitioning Into Minimum Number Of Deci-Binary Numbers](./solutions/1689-partitioning-into-minimum-number-of-deci-binary-numbers.js)|Medium|
 1690|[Stone Game VII](./solutions/1690-stone-game-vii.js)|Medium|
 1691|[Maximum Height by Stacking Cuboids](./solutions/1691-maximum-height-by-stacking-cuboids.js)|Hard|
+1694|[Reformat Phone Number](./solutions/1694-reformat-phone-number.js)|Easy|
 1716|[Calculate Money in Leetcode Bank](./solutions/1716-calculate-money-in-leetcode-bank.js)|Easy|
 1718|[Construct the Lexicographically Largest Valid Sequence](./solutions/1718-construct-the-lexicographically-largest-valid-sequence.js)|Medium|
 1726|[Tuple with Same Product](./solutions/1726-tuple-with-same-product.js)|Medium|
diff --git a/solutions/1694-reformat-phone-number.js b/solutions/1694-reformat-phone-number.js
@@ -0,0 +1,46 @@
+/**
+ * 1694. Reformat Phone Number
+ * https://leetcode.com/problems/reformat-phone-number/
+ * Difficulty: Easy
+ *
+ * You are given a phone number as a string number. number consists of digits, spaces ' ',
+ * and/or dashes '-'.
+ *
+ * You would like to reformat the phone number in a certain manner. Firstly, remove all spaces
+ * and dashes. Then, group the digits from left to right into blocks of length 3 until there
+ * are 4 or fewer digits. The final digits are then grouped as follows:
+ * - 2 digits: A single block of length 2.
+ * - 3 digits: A single block of length 3.
+ * - 4 digits: Two blocks of length 2 each.
+ *
+ * The blocks are then joined by dashes. Notice that the reformatting process should never produce
+ * any blocks of length 1 and produce at most two blocks of length 2.
+ *
+ * Return the phone number after formatting.
+ */
+
+/**
+ * @param {string} number
+ * @return {string}
+ */
+var reformatNumber = function(number) {
+  const digits = number.replace(/[^0-9]/g, '');
+  const blocks = [];
+  let i = 0;
+
+  while (i < digits.length) {
+    const remaining = digits.length - i;
+    if (remaining > 4) {
+      blocks.push(digits.slice(i, i + 3));
+      i += 3;
+    } else if (remaining === 4) {
+      blocks.push(digits.slice(i, i + 2), digits.slice(i + 2));
+      break;
+    } else if (remaining === 2 || remaining === 3) {
+      blocks.push(digits.slice(i));
+      break;
+    }
+  }
+
+  return blocks.join('-');
+};
