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2016/19-An Elephant Named Joseph.py

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# -------------------------------- Input data -------------------------------- #
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import os, math
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test_data = {}
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test = 1
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test_data[test] = {"input": 5,
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"expected": [3, 'Unknown'],
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}
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test += 1
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test_data[test] = {"input": 15,
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"expected": ['Unknown', 'Unknown'],
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}
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test = 'real'
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test_data[test] = {"input": 3012210,
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"expected": ['1830117', '1417887'],
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}
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# -------------------------------- Control program execution -------------------------------- #
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case_to_test = 'real'
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part_to_test = 2
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verbose_level = 1
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# -------------------------------- Initialize some variables -------------------------------- #
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puzzle_input = test_data[case_to_test]['input']
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puzzle_expected_result = test_data[case_to_test]['expected'][part_to_test-1]
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puzzle_actual_result = 'Unknown'
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# -------------------------------- Actual code execution -------------------------------- #
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if part_to_test == 1:
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elves = list(range(1, puzzle_input + 1))
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while len(elves) > 1:
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if len(elves) %2 == 1:
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elves = elves[::2][1:]
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else:
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elves = elves[::2]
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puzzle_actual_result = elves[0]
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else:
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# For some reason, the value for any power of 3 is equal to itself
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# If X is a power of 3:
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# Numbers N from X+1 to 2*X have N-X as a result (it increases by 1)
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# Numbers N from 2*X to 3*X-1 have 2*N-3*X as a result (it increases by 2)
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# Find the power of 3 right below the puzzle input
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power_of_3 = 3**math.trunc(math.log(puzzle_input, 3))
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if puzzle_input <= 2*power_of_3:
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puzzle_actual_result = puzzle_input - power_of_3
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else:
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puzzle_actual_result = puzzle_input*2 - power_of_3*3
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# -------------------------------- Outputs / results -------------------------------- #
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if verbose_level >= 3:
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print ('Input : ' + puzzle_input)
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print ('Expected result : ' + str(puzzle_expected_result))
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print ('Actual result : ' + str(puzzle_actual_result))
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