Skip to content

Commit 95cab08

Browse files
committed
Switch to a functional approach instead of class-based.
Use proper JSDoc comments. Refine the comments and remove redundancies.
1 parent f945eb1 commit 95cab08

File tree

2 files changed

+45
-63
lines changed

2 files changed

+45
-63
lines changed

Backtracking/MColoringProblem.js

Lines changed: 39 additions & 55 deletions
Original file line numberDiff line numberDiff line change
@@ -1,65 +1,49 @@
1-
/*
2-
Problem: M Coloring Problem
3-
Given a graph represented as an adjacency matrix and a number M (number of colors),
4-
determine if the graph can be colored with up to M colors such that no two adjacent
5-
vertices share the same color.
1+
//https://en.wikipedia.org/wiki/Edge_coloring
62

7-
What is the M Coloring Problem?
8-
- This problem is about coloring a graph's vertices with at most M different colors
9-
such that no two adjacent vertices have the same color.
3+
// M Coloring Problem
4+
// Given an adjacency matrix representation of a graph and a number M,
5+
// determine if the graph can be colored with up to M colors such that
6+
// no two adjacent vertices share the same color.
107

11-
Example:
12-
- Consider a triangle (3 nodes connected cyclically). We'd need 3 colors to color each vertex
13-
without adjacent vertices having the same color.
8+
function mColoring(graph, m) {
9+
const colors = new Array(graph.length).fill(0);
1410

15-
Solution:
16-
- We will be using backtracking to solve this question.
17-
- Color a vertex, then move to an adjacent vertex and try all colors. If a color is valid,
18-
continue to the next vertex, else backtrack.
19-
*/
20-
21-
class MColoring {
22-
constructor(graph, m) {
23-
this.graph = graph; // adjacency matrix representation
24-
this.m = m;
25-
this.colors = new Array(graph.length).fill(0);
26-
}
27-
28-
isSafe(vertex, color) {
29-
for (let i = 0; i < this.graph.length; i++) {
30-
if (this.graph[vertex][i] && this.colors[i] === color) {
31-
return false;
32-
}
11+
// Check if it's safe to color a vertex with a given color.
12+
function isSafe(vertex, color) {
13+
for (let i = 0; i < graph.length; i++) {
14+
if (graph[vertex][i] && colors[i] === color) {
15+
return false;
3316
}
17+
}
18+
return true;
19+
}
20+
21+
// Use backtracking to try and color the graph.
22+
function solveColoring(vertex = 0) {
23+
if (vertex === graph.length) {
3424
return true;
3525
}
36-
37-
solveColoring(vertex = 0) {
38-
if (vertex === this.graph.length) {
39-
return true;
40-
}
41-
42-
for (let color = 1; color <= this.m; color++) {
43-
if (this.isSafe(vertex, color)) {
44-
this.colors[vertex] = color;
45-
46-
if (this.solveColoring(vertex + 1)) {
47-
return true;
48-
}
49-
50-
this.colors[vertex] = 0; // backtrack
26+
27+
for (let color = 1; color <= m; color++) {
28+
if (isSafe(vertex, color)) {
29+
colors[vertex] = color;
30+
31+
if (solveColoring(vertex + 1)) {
32+
return true;
5133
}
34+
35+
// If no solution, backtrack.
36+
colors[vertex] = 0;
5237
}
53-
return false;
54-
}
55-
56-
getSolution() {
57-
if (this.solveColoring()) {
58-
return this.colors;
59-
}
60-
return [];
6138
}
39+
return false;
6240
}
63-
64-
export { MColoring }
65-
41+
42+
// If coloring is possible, return the colors.
43+
if (solveColoring()) {
44+
return colors;
45+
}
46+
return null;
47+
}
48+
49+
export { mColoring };
Lines changed: 6 additions & 8 deletions
Original file line numberDiff line numberDiff line change
@@ -1,4 +1,4 @@
1-
import { MColoring } from '../MColoringProblem';
1+
import { mColoring } from '../MColoringProblem';
22

33
describe('MColoringProblem', () => {
44
it('should color a triangle with 3 colors', () => {
@@ -7,9 +7,8 @@ describe('MColoringProblem', () => {
77
[1, 0, 1],
88
[1, 1, 0]
99
];
10-
const test1 = new MColoring(graph, 3);
11-
const solution = test1.getSolution();
12-
expect(solution).not.toEqual([]);
10+
const solution = mColoring(graph, 3);
11+
expect(solution).not.toBeNull();
1312
});
1413

1514
it('should not color a triangle with 2 colors', () => {
@@ -18,8 +17,7 @@ describe('MColoringProblem', () => {
1817
[1, 0, 1],
1918
[1, 1, 0]
2019
];
21-
const test2 = new MColoring(graph, 2);
22-
const solution = test2.getSolution();
23-
expect(solution).toEqual([]);
20+
const solution = mColoring(graph, 2);
21+
expect(solution).toBeNull();
2422
});
25-
});
23+
});

0 commit comments

Comments
 (0)
pFad - Phonifier reborn

Pfad - The Proxy pFad of © 2024 Garber Painting. All rights reserved.

Note: This service is not intended for secure transactions such as banking, social media, email, or purchasing. Use at your own risk. We assume no liability whatsoever for broken pages.


Alternative Proxies:

Alternative Proxy

pFad Proxy

pFad v3 Proxy

pFad v4 Proxy