|
27 | 27 | */
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28 | 28 |
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29 | 29 | public class _538 {
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30 |
| - //This solution is generic for both BST and regular binary trees |
31 |
| - public TreeNode convertBST(TreeNode root) { |
32 |
| - if (root == null) return root; |
33 |
| - List<Integer> list = new ArrayList<>(); |
34 |
| - putNodeToList(list, root); |
35 |
| - Collections.sort(list); |
36 |
| - int[] sums = new int[list.size()]; |
37 |
| - sums[list.size()-1] = 0; |
38 |
| - for (int i = list.size()-2; i >= 0; i--) { |
39 |
| - sums[i] = sums[i+1] + list.get(i+1); |
| 30 | + |
| 31 | + public static class BSTSolution { |
| 32 | + /**reference: https://discuss.leetcode.com/topic/83455/java-recursive-o-n-time/13 |
| 33 | + * |
| 34 | + * A reversed version of inorder traversal: right -> root -> left*/ |
| 35 | + public TreeNode convertBST(TreeNode root) { |
| 36 | + dfs(root, 0); |
| 37 | + return root; |
40 | 38 | }
|
41 |
| - TreeMap<Integer, Integer> treeMap = new TreeMap<>(); |
42 |
| - for (int i = 0; i < list.size(); i++) { |
43 |
| - treeMap.put(list.get(i), sums[i]); |
| 39 | + |
| 40 | + private int dfs(TreeNode root, int val) { |
| 41 | + if (root == null) return val; |
| 42 | + int right = dfs(root.right, val); |
| 43 | + root.val += right; |
| 44 | + int left = dfs(root.left, root.val); |
| 45 | + return left; |
44 | 46 | }
|
45 |
| - TreeNode result = new TreeNode(treeMap.get(list.get(0))); |
46 |
| - return generateResultRoot(root, treeMap, result); |
47 | 47 | }
|
48 | 48 |
|
49 |
| - private TreeNode generateResultRoot(TreeNode root, TreeMap<Integer, Integer> treeMap, TreeNode result) { |
50 |
| - if (root != null) result.val = treeMap.get(root.val) + root.val; |
51 |
| - if (root.left != null) { |
52 |
| - result.left = new TreeNode(0); |
53 |
| - generateResultRoot(root.left, treeMap, result.left); |
| 49 | + public static class GenericSolution { |
| 50 | + //This solution is generic for both BST and regular binary trees |
| 51 | + public TreeNode convertBST(TreeNode root) { |
| 52 | + if (root == null) return root; |
| 53 | + List<Integer> list = new ArrayList<>(); |
| 54 | + putNodeToList(list, root); |
| 55 | + Collections.sort(list); |
| 56 | + int[] sums = new int[list.size()]; |
| 57 | + sums[list.size() - 1] = 0; |
| 58 | + for (int i = list.size() - 2; i >= 0; i--) { |
| 59 | + sums[i] = sums[i + 1] + list.get(i + 1); |
| 60 | + } |
| 61 | + TreeMap<Integer, Integer> treeMap = new TreeMap<>(); |
| 62 | + for (int i = 0; i < list.size(); i++) { |
| 63 | + treeMap.put(list.get(i), sums[i]); |
| 64 | + } |
| 65 | + TreeNode result = new TreeNode(treeMap.get(list.get(0))); |
| 66 | + return generateResultRoot(root, treeMap, result); |
54 | 67 | }
|
55 |
| - if (root.right != null) { |
56 |
| - result.right = new TreeNode(0); |
57 |
| - generateResultRoot(root.right, treeMap, result.right); |
| 68 | + |
| 69 | + private TreeNode generateResultRoot(TreeNode root, TreeMap<Integer, Integer> treeMap, TreeNode result) { |
| 70 | + if (root != null) result.val = treeMap.get(root.val) + root.val; |
| 71 | + if (root.left != null) { |
| 72 | + result.left = new TreeNode(0); |
| 73 | + generateResultRoot(root.left, treeMap, result.left); |
| 74 | + } |
| 75 | + if (root.right != null) { |
| 76 | + result.right = new TreeNode(0); |
| 77 | + generateResultRoot(root.right, treeMap, result.right); |
| 78 | + } |
| 79 | + return result; |
58 | 80 | }
|
59 |
| - return result; |
60 |
| - } |
61 | 81 |
|
62 |
| - private void putNodeToList(List<Integer> list, TreeNode root) { |
63 |
| - if (root != null) list.add(root.val); |
64 |
| - if (root.left != null) putNodeToList(list, root.left); |
65 |
| - if (root.right != null) putNodeToList(list, root.right); |
| 82 | + private void putNodeToList(List<Integer> list, TreeNode root) { |
| 83 | + if (root != null) list.add(root.val); |
| 84 | + if (root.left != null) putNodeToList(list, root.left); |
| 85 | + if (root.right != null) putNodeToList(list, root.right); |
| 86 | + } |
66 | 87 | }
|
67 |
| - |
68 | 88 | }
|
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