1+ -- 1083. Sales Analysis II
2+ --
3+ -- Table: Product
4+ --
5+ -- +--------------+---------+
6+ -- | Column Name | Type |
7+ -- +--------------+---------+
8+ -- | product_id | int |
9+ -- | product_name | varchar |
10+ -- | unit_price | int |
11+ -- +--------------+---------+
12+ -- product_id is the primary key of this table.
13+ -- Table: Sales
14+ --
15+ -- +-------------+---------+
16+ -- | Column Name | Type |
17+ -- +-------------+---------+
18+ -- | seller_id | int |
19+ -- | product_id | int |
20+ -- | buyer_id | int |
21+ -- | sale_date | date |
22+ -- | quantity | int |
23+ -- | price | int |
24+ -- +------ ------+---------+
25+ -- This table has no primary key, it can have repeated rows.
26+ -- product_id is a foreign key to Product table.
27+ --
28+ --
29+ -- Write an SQL query that reports the buyers who have bought S8 but not iPhone. Note that S8 and iPhone are products present in the Product table.
30+ --
31+ -- The query result format is in the following example:
32+ --
33+ -- Product table:
34+ -- +------------+--------------+------------+
35+ -- | product_id | product_name | unit_price |
36+ -- +------------+--------------+------------+
37+ -- | 1 | S8 | 1000 |
38+ -- | 2 | G4 | 800 |
39+ -- | 3 | iPhone | 1400 |
40+ -- +------------+--------------+------------+
41+ --
42+ -- Sales table:
43+ -- +-----------+------------+----------+------------+----------+-------+
44+ -- | seller_id | product_id | buyer_id | sale_date | quantity | price |
45+ -- +-----------+------------+----------+------------+----------+-------+
46+ -- | 1 | 1 | 1 | 2019-01-21 | 2 | 2000 |
47+ -- | 1 | 2 | 2 | 2019-02-17 | 1 | 800 |
48+ -- | 2 | 1 | 3 | 2019-06-02 | 1 | 800 |
49+ -- | 3 | 3 | 3 | 2019-05-13 | 2 | 2800 |
50+ -- +-----------+------------+----------+------------+----------+-------+
51+ --
52+ -- Result table:
53+ -- +-------------+
54+ -- | buyer_id |
55+ -- +-------------+
56+ -- | 1 |
57+ -- +-------------+
58+ -- The buyer with id 1 bought an S8 but didn't buy an iPhone. The buyer with id 3 bought both.
59+
60+ -- # Write your MySQL query statement below
61+ select distinct buyer_id from Sales s
62+ join Product p
63+ on p .product_id = s .product_id
64+ where p .product_name = ' S8'
65+ and buyer_id not in
66+ (
67+ select buyer_id from Sales s
68+ join Product p on p .product_id = s .product_id
69+ where p .product_name = ' iPhone'
70+ )
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