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Update 6-store-relationships-in-dictionaries.py
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ch09-lists-tuples-and-dictionaries/6-store-relationships-in-dictionaries.py

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captains["Discovery"] = "unknown"
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# Bonus points: you could instead loop over a list of names to check
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# for name in ["Enterprise", "Discovery"]:
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# for ship in ["Enterprise", "Discovery"]:
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# if not ship in captains:
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# captains[ship] = "unknown"
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