From c7f8b0f368a94ab19d528411c72f4b81c15cca71 Mon Sep 17 00:00:00 2001 From: jxu <7989982+jxu@users.noreply.github.com> Date: Mon, 16 Jan 2023 22:34:04 -0500 Subject: [PATCH] Link extended Euclidean algorithm to site article --- src/algebra/module-inverse.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/src/algebra/module-inverse.md b/src/algebra/module-inverse.md index b17b7af78..f18def09b 100644 --- a/src/algebra/module-inverse.md +++ b/src/algebra/module-inverse.md @@ -28,7 +28,7 @@ Consider the following equation (with unknown $x$ and $y$): $$a \cdot x + m \cdot y = 1$$ This is a [Linear Diophantine equation in two variables](linear-diophantine-equation.md). -As shown in the linked article, when $\gcd(a, m) = 1$, the equation has a solution which can be found using the [extended Euclidean algorithm](http://en.wikipedia.org/wiki/Extended_Euclidean_algorithm). +As shown in the linked article, when $\gcd(a, m) = 1$, the equation has a solution which can be found using the [extended Euclidean algorithm](extended-euclid-algorithm.md). Note that $\gcd(a, m) = 1$ is also the condition for the modular inverse to exist. Now, if we take modulo $m$ of both sides, we can get rid of $m \cdot y$, and the equation becomes:
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