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README.md

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- [7562](https://www.acmicpc.net/problem/7562) : 나이트의 이동 = [풀이](https://github.com/devOTTO/Algorithm-Study/blob/master/baekjoon/7562.cpp)
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- [10026](https://www.acmicpc.net/problem/10026) : 적록색약 = [풀이](https://github.com/devOTTO/Algorithm-Study/blob/master/baekjoon/10026.cpp)
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- [2468](https://www.acmicpc.net/problem/2468) : 안전영역 = [풀이](https://github.com/devOTTO/Algorithm-Study/blob/master/baekjoon/2468.cpp)
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- [2573](https://www.acmicpc.net/problem/2573) : 빙산 = [풀이](https://github.com/devOTTO/Algorithm-Study/blob/master/baekjoon/2573.cpp)
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#### 백트랙킹/시뮬레이션

baekjoon/2573.cpp

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//
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// Created by 융미 on 2019-04-23.
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//2573 빙산
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#include <iostream>
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#include <queue>
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#include <utility>
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#include <cstring>
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#include <algorithm>
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using namespace std;
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#define MAX 300
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int dx[4] = {-1,1,0,0};
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int dy[4] = {0,0,1,-1};
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int n, m;
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int age;
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int arr[MAX][MAX];
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bool vis[MAX][MAX];
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void getInput(); //입력 함수
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void getAge(); //시간 지나는 함수
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int check(); //덩어리 체크 함수
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void printOutput(); //결과 출력 함수
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int main(){
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ios::sync_with_stdio(0);
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cin.tie(0);
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getInput();
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printOutput();
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return 0;
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}
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void getInput()
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{
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cin >> n >> m;
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for(int i = 0; i<n; i++)
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{
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for(int j = 0; j<m; j++)
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cin >> arr[i][j];
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}
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}
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void printOutput()
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{
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int result = 1;
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while(true)
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{
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age++;
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getAge();
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result = check();
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if(result >= 2) {cout << age; break;}
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if(result == 0) {cout << 0; break;}
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}
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}
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void getAge(){
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int tempArr[MAX][MAX];
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memset(tempArr,0,sizeof(tempArr));
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for(int i = 1; i<n-1; i++)
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{
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for(int j = 1; j<m-1; j++)
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{
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if(arr[i][j] == 0) continue;
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int count = 0;
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for(int k = 0; k<4; k++){
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int nx = i + dx[k];
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int ny = j + dy[k];
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if(nx < 0 || nx >= n || ny < 0 || ny >= m) continue;
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if(arr[nx][ny] != 0) continue;
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count++;
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}
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tempArr[i][j] = arr[i][j] - count;
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if(tempArr[i][j] < 0) tempArr[i][j] = 0; //0 보다 작을 수 없다. 이조건 때문에 2번 틀림..
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};
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}
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memcpy(arr,tempArr, sizeof(arr));
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}
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int check(){
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memset(vis, 0, sizeof(vis));
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int count = 0;
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for(int i = 1; i<n-1; i++)
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{
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for(int j = 1; j<m-1; j++)
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{
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if(arr[i][j] == 0 || vis[i][j] == 1) continue;
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queue<pair<int,int>> q;
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q.push({i,j});
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vis[i][j] = 1;
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while(!q.empty())
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{
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auto cur = q.front();
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q.pop();
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for(int k = 0; k<4; k++)
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{
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int nx = cur.first + dx[k];
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int ny = cur.second + dy[k];
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if(nx < 1 || nx >= n-1 || ny < 1 || ny >= m-1) continue;
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if(arr[nx][ny] == 0 || vis[nx][ny] == 1) continue;
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q.push({nx,ny});
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vis[nx][ny] = 1;
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}
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}
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count++;
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}
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}
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return count;
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}
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