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Implemented Partition Problem, Recursive problem (TheAlgorithms#1582)
* Add Tug of War solution using backtracking * Updated Documentation in README.md * Added Tug of war problem link * Updated Documentation in README.md * Updated Documentation in README.md * Refactor tugOfWar: remove unused vars, optimize initialization, and remove redundant checks * Added Function Export Statment * Updated Documentation in README.md * Resolved Code Style --Prettier * Rename "backtrack" to "recurse" * Fix test case: The difference needs to be exactly 1. * Code Modification: subsets should have sizes as close to n/2 as possible * Updated test-case of TugOfWar * Changed TugOfWar problem to Partition * Modified partition problem * Updated Documentation in README.md * fixed code style --------- Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com> Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
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DIRECTORY.md

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* [NumberOfIslands](Graphs/NumberOfIslands.js)
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* [PrimMST](Graphs/PrimMST.js)
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* **Hashes**
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* [MD5](Hashes/MD5.js)
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* [SHA1](Hashes/SHA1.js)
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* [SHA256](Hashes/SHA256.js)
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* **Maths**
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* [KochSnowflake](Recursive/KochSnowflake.js)
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* [LetterCombination](Recursive/LetterCombination.js)
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* [Palindrome](Recursive/Palindrome.js)
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* [Partition](Recursive/Partition.js)
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* [SubsequenceRecursive](Recursive/SubsequenceRecursive.js)
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* [TowerOfHanoi](Recursive/TowerOfHanoi.js)
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* **Search**

Recursive/Partition.js

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/**
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* @function canPartition
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* @description Check whether it is possible to partition the given array into two equal sum subsets using recursion.
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* @param {number[]} nums - The input array of numbers.
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* @param {number} index - The current index in the array being considered.
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* @param {number} target - The target sum for each subset.
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* @return {boolean}.
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* @see [Partition Problem](https://en.wikipedia.org/wiki/Partition_problem)
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*/
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const canPartition = (nums, index = 0, target = 0) => {
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if (!Array.isArray(nums)) {
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throw new TypeError('Invalid Input')
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}
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const sum = nums.reduce((acc, num) => acc + num, 0)
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if (sum % 2 !== 0) {
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return false
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}
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if (target === sum / 2) {
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return true
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}
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if (index >= nums.length || target > sum / 2) {
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return false
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}
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// Include the current number in the first subset and check if a solution is possible.
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const withCurrent = canPartition(nums, index + 1, target + nums[index])
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// Exclude the current number from the first subset and check if a solution is possible.
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const withoutCurrent = canPartition(nums, index + 1, target)
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return withCurrent || withoutCurrent
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}
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export { canPartition }

Recursive/test/Partition.test.js

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import { canPartition } from '../Partition'
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describe('Partition (Recursive)', () => {
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it('expects to return true for an array that can be partitioned', () => {
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const result = canPartition([1, 5, 11, 5])
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expect(result).toBe(true)
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})
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it('expects to return false for an array that cannot be partitioned', () => {
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const result = canPartition([1, 2, 3, 5])
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expect(result).toBe(false)
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})
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it('expects to return true for an empty array (0 elements)', () => {
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const result = canPartition([])
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expect(result).toBe(true)
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})
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it('Throw Error for Invalid Input', () => {
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expect(() => canPartition(123)).toThrow('Invalid Input')
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expect(() => canPartition(null)).toThrow('Invalid Input')
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expect(() => canPartition(undefined)).toThrow('Invalid Input')
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})
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})

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