_thread.start_new_thread: How to use kwargs #17584
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Baffled by My function to spawn as a thread has this signature: Allright, so I remove those args to get this signature: Other attempts: MicroPython v1.25.0 on 2025-04-15; Generic ESP32 module with ESP32 |
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Replies: 2 comments 3 replies
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I don't know the details of your script, but maybe this will help: import _thread
import time
class test():
def serverReport(self, id, what):
print(f'ID: {id[0]}/{id[1]}, CMD: {what['cmd']} {what['val']}')
t = test()
# t.serverReport(('PRG', 123), {'cmd':'add', 'val':(3,4)})
# new_thread(func, (param))
_thread.start_new_thread(t.serverReport, (('PRG', 123), {'cmd':'add', 'val':(3,4)}))
time.sleep(5) # wait a bit
print('Done!')This will give: |
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Gosh, I'd never have guessed, but it's correct, it works! Declare one extra arg in the function to be spawned as a signal to the Pythonic machinery. When invoking, supply one single actual arg, a tuple. The first element of the tuple will be taken as the Many thanks! P.S. I'm just a little worried that combining everything into a single tuple will cause object allocation. |
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Follow up: It seems the second element of the tuple can be anything. I can't explain why the docs say it specifies a dictionary of keyword arguments. |
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The args must be presented to import _thread
import time
class test():
def serverReport(self, id, num, cmd, val): # two positional args and two kwargs
print(f'ID: {id}, num {num}, cmd {cmd}, val {val}')
t = test()
_thread.start_new_thread(t.serverReport, ('PRG', 123), {'cmd':'add', 'val':(3,4)})
time.sleep(5) # wait a bit
print('Done!')prints: ID: PRG, num 123, cmd add, val (3, 4) |
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Great clarification. I'm still getting used to Python... |
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I don't know the details of your script, but maybe this will help:
This will give: