fix(subset): check any as superset

James Chen-Smith · isaacs · commit 15ed20833cb5 · 2021-03-22T11:45:25.000-07:00
Adds short-circuit check if superset is `*`. PR-URL: #375 Credit: @jameschensmith Close: #375 Reviewed-by: @isaacs
diff --git a/ranges/subset.js b/ranges/subset.js
@@ -7,6 +7,8 @@ const compare = require('../functions/compare.js')
 // - Every simple range `r1, r2, ...` is a subset of some `R1, R2, ...`
 //
 // Simple range `c1 c2 ...` is a subset of simple range `C1 C2 ...` iff:
+// - If C is only the ANY comparator
+//   - return true
 // - If c is only the ANY comparator
 //   - If C is only the ANY comparator, return true
 //   - Else return false
@@ -58,6 +60,9 @@ const simpleSubset = (sub, dom, options) => {
   if (sub === dom)
     return true
 
+  if (dom.length === 1 && dom[0].semver === ANY)
+    return true
+
   if (sub.length === 1 && sub[0].semver === ANY)
     return dom.length === 1 && dom[0].semver === ANY
 
diff --git a/test/ranges/subset.js b/test/ranges/subset.js
@@ -15,6 +15,12 @@ const cases = [
   ['>2 <1', '3', true],
   ['1 || 2 || 3', '>=1.0.0', true],
 
+  // everything is a subset of *
+  ['1.2.3', '*', true],
+  ['^1.2.3', '*', true],
+  ['^1.2.3-pre.0', '*', true],
+  ['1 || 2 || 3', '*', true],
+
   ['*', '*', true],
   ['', '*', true],
   ['*', '', true],
