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README.md

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|779|[K-th Symbol in Grammar](https://leetcode.com/problems/k-th-symbol-in-grammar/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_779.java) | O(logn) | O(1) | |Medium|
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|776|[Split BST](https://leetcode.com/problems/split-bst/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_776.java) | O(n) | O(n) | |Medium| Recursion
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|771|[Jewels and Stones](https://leetcode.com/problems/jewels-and-stones/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_771.java) | O(n) | O(m) | |Easy|
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|769|[Max Chunks To Make Sorted](https://leetcode.com/problems/max-chunks-to-make-sorted/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_769.java) | O(n) | O(1) | |Medium| Array
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|767|[Reorganize String](https://leetcode.com/problems/reorganize-string/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_767.java) | O(klogk) k is the number of unique characters in given String| O(k) | |Medium|
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|766|[Toeplitz Matrix](https://leetcode.com/problems/toeplitz-matrix/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_766.java) | O(m*n) | O(1) | |Easy|
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|765|[Couples Holding Hands](https://leetcode.com/problems/couples-holding-hands/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_765.java) | O(n^2) | O(1) | |Hard|
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package com.fishercoder.solutions;
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/**
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* 769. Max Chunks To Make Sorted
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Given an array arr that is a permutation of [0, 1, ..., arr.length - 1], we split the array into some number of "chunks" (partitions), and individually sort each chunk.
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After concatenating them, the result equals the sorted array.
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What is the most number of chunks we could have made?
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Example 1:
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Input: arr = [4,3,2,1,0]
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Output: 1
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Explanation:
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Splitting into two or more chunks will not return the required result.
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For example, splitting into [4, 3], [2, 1, 0] will result in [3, 4, 0, 1, 2], which isn't sorted.
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Example 2:
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Input: arr = [1,0,2,3,4]
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Output: 4
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Explanation:
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We can split into two chunks, such as [1, 0], [2, 3, 4].
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However, splitting into [1, 0], [2], [3], [4] is the highest number of chunks possible.
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Note:
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arr will have length in range [1, 10].
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arr[i] will be a permutation of [0, 1, ..., arr.length - 1].
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*/
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public class _769 {
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public static class Solution1 {
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/**credit: https://leetcode.com/problems/max-chunks-to-make-sorted/discuss/113520/Java-solution-left-max-and-right-min.*/
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public int maxChunksToSorted(int[] arr) {
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int len = arr.length;
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int[] maxOfLeft = new int[len];
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maxOfLeft[0] = arr[0];
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for (int i = 1; i < len; i++) {
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maxOfLeft[i] = Math.max(arr[i], maxOfLeft[i - 1]);
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}
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int[] minOfRight = new int[len];
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minOfRight[len - 1] = arr[len - 1];
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for (int i = len - 2; i >= 0; i--) {
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minOfRight[i] = Math.min(minOfRight[i + 1], arr[i]);
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}
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int result = 0;
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for (int i = 0; i < len - 1; i++) {
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if (maxOfLeft[i] <= minOfRight[i + 1]) {
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result++;
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}
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}
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return result + 1;
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}
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}
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public static class Solution2 {
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/**credit: https://leetcode.com/articles/max-chunks-to-make-sorted-i/*/
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public int maxChunksToSorted(int[] arr) {
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int ans = 0, max = 0;
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for (int i = 0; i < arr.length; ++i) {
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max = Math.max(max, arr[i]);
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if (max == i) ans++;
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}
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return ans;
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}
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}
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}
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package com.fishercoder;
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import com.fishercoder.solutions._769;
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import org.junit.BeforeClass;
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import org.junit.Test;
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import static org.junit.Assert.assertEquals;
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public class _769Test {
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private static _769.Solution1 solution1;
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private static _769.Solution2 solution2;
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private static int[] arr;
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@BeforeClass
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public static void setup() {
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solution1 = new _769.Solution1();
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solution2 = new _769.Solution2();
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}
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@Test
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public void test1() {
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arr = new int[] {4, 3, 2, 1, 0};
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assertEquals(1, solution1.maxChunksToSorted(arr));
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assertEquals(1, solution2.maxChunksToSorted(arr));
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}
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@Test
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public void test2() {
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arr = new int[] {1, 0, 2, 3, 4};
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assertEquals(4, solution1.maxChunksToSorted(arr));
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assertEquals(4, solution2.maxChunksToSorted(arr));
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}
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}

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