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README.md

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| # | Title | Solutions | Time | Space | Video | Difficulty | Tag
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|-----|----------------|---------------|---------------|---------------|--------|-------------|-------------
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|767|[Reorganize String](https://leetcode.com/problems/reorganize-string/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_767.java) | O(klogk) k is the number of unique characters in given String| O(k) | |Medium|
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|766|[Toeplitz Matrix](https://leetcode.com/problems/toeplitz-matrix/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_766.java) | O(m*n) | O(1) | |Easy|
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|765|[Couples Holding Hands](https://leetcode.com/problems/couples-holding-hands/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_765.java) | O(n^2) | O(1) | |Hard|
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|764|[Largest Plus Sign](https://leetcode.com/problems/largest-plus-sign/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_764.java) | O(n^2) | O(n^2) | |Medium| DP
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package com.fishercoder.solutions;
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import java.util.HashMap;
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import java.util.Map;
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import java.util.PriorityQueue;
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/**
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* 767. Reorganize String
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*
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* Given a string S, check if the letters can be rearranged so that two characters that are adjacent to each other are not the same.
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If possible, output any possible result. If not possible, return the empty string.
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Example 1:
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Input: S = "aab"
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Output: "aba"
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Example 2:
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Input: S = "aaab"
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Output: ""
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Note:
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S will consist of lowercase letters and have length in range [1, 500].
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*/
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public class _767 {
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public static class Solution1 {
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public String reorganizeString(String S) {
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Map<Character, Integer> map = new HashMap<>();
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for (char c : S.toCharArray()) {
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map.put(c, map.getOrDefault(c, 0) + 1);
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}
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int len = S.length();
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for (char c : map.keySet()) {
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if ((len % 2 == 0 && map.get(c) > len / 2) || (len % 2 != 0 && map.get(c) >= len / 2 + 2)) {
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return "";
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}
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}
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PriorityQueue<CustChar> queue = new PriorityQueue<>((a, b) -> b.count - a.count);
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for (char c : map.keySet()) {
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queue.offer(new CustChar(c, map.get(c)));
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}
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StringBuilder sb = new StringBuilder();
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while (!queue.isEmpty()) {
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CustChar curr = queue.poll();
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char c = curr.c;
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if (sb.length() > 0 && sb.charAt(sb.length() - 1) != c) {
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sb.append(c);
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if (curr.count > 1) {
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queue.offer(new CustChar(c, curr.count - 1));
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}
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} else if (sb.length() == 0) {
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sb.append(c);
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if (curr.count > 1) {
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queue.offer(new CustChar(c, curr.count - 1));
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}
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} else if (sb.length() > 0 && sb.charAt(sb.length() - 1) == c && !queue.isEmpty()) {
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CustChar next = queue.poll();
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sb.append(next.c);
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if (next.count > 1) {
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queue.offer(new CustChar(next.c, next.count - 1));
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}
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queue.offer(curr);
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}
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}
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return sb.toString();
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}
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class CustChar {
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Character c;
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int count;
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public CustChar(Character c, int count) {
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this.c = c;
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this.count = count;
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}
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}
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}
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}
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package com.fishercoder;
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import com.fishercoder.solutions._767;
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import org.junit.BeforeClass;
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import org.junit.Test;
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import static org.junit.Assert.assertEquals;
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public class _767Test {
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private static _767.Solution1 solution1;
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@BeforeClass
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public static void setup() {
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solution1 = new _767.Solution1();
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}
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@Test
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public void test1() {
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assertEquals("aba", solution1.reorganizeString("aab"));
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}
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@Test
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public void test2() {
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assertEquals("", solution1.reorganizeString("aaab"));
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}
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@Test
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public void test3() {
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assertEquals("bababab", solution1.reorganizeString("aaabbbb"));
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}
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@Test
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public void test4() {
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assertEquals("vovlv", solution1.reorganizeString("vvvlo"));
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}
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}

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