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+## 1. Brute Force
+
+::tabs-start
+
+```python
+class Solution:
+    def leastBricks(self, wall: List[List[int]]) -> int:
+        n = len(wall)
+        m = 0
+        for brick in wall[0]:
+            m += brick
+
+        gaps = [[] for _ in range(n)]
+        for i in range(n):
+            gap = 0
+            for brick in wall[i]:
+                gap += brick
+                gaps[i].append(gap)
+        
+        res = n
+        for line in range(1, m):
+            cuts = 0
+            for i in range(n):
+                if line not in gaps[i]:
+                    cuts += 1
+            
+            res = min(res, cuts)
+        return res
+```
+
+```java
+public class Solution {
+    public int leastBricks(List<List<Integer>> wall) {
+        int n = wall.size();
+        int m = 0;
+        for (int brick : wall.get(0)) {
+            m += brick;
+        }
+
+        List<List<Integer>> gaps = new ArrayList<>();
+        for (int i = 0; i < n; i++) {
+            gaps.add(new ArrayList<>());
+            int gap = 0;
+            for (int brick : wall.get(i)) {
+                gap += brick;
+                gaps.get(i).add(gap);
+            }
+        }
+
+        int res = n;
+        for (int line = 1; line < m; line++) {
+            int cuts = 0;
+            for (int i = 0; i < n; i++) {
+                if (!gaps.get(i).contains(line)) {
+                    cuts++;
+                }
+            }
+            res = Math.min(res, cuts);
+        }
+
+        return res;
+    }
+}
+```
+
+```cpp
+class Solution {
+public:
+    int leastBricks(vector<vector<int>>& wall) {
+        int n = wall.size();
+        int m = 0;
+        for (int brick : wall[0]) {
+            m += brick;
+        }
+
+        vector<vector<int>> gaps(n);
+        for (int i = 0; i < n; i++) {
+            int gap = 0;
+            for (int brick : wall[i]) {
+                gap += brick;
+                gaps[i].push_back(gap);
+            }
+        }
+
+        int res = n;
+        for (int line = 1; line < m; line++) {
+            int cuts = 0;
+            for (int i = 0; i < n; i++) {
+                if (find(gaps[i].begin(), gaps[i].end(), line) == gaps[i].end()) {
+                    cuts++;
+                }
+            }
+            res = min(res, cuts);
+        }
+
+        return res;
+    }
+};
+```
+
+```javascript
+class Solution {
+    /**
+     * @param {number[][]} wall
+     * @return {number}
+     */
+    leastBricks(wall) {
+        const n = wall.length;
+        let m = 0;
+        for (const brick of wall[0]) {
+            m += brick;
+        }
+
+        const gaps = Array.from({ length: n }, () => []);
+        for (let i = 0; i < n; i++) {
+            let gap = 0;
+            for (const brick of wall[i]) {
+                gap += brick;
+                gaps[i].push(gap);
+            }
+        }
+
+        let res = n;
+        for (let line = 1; line < m; line++) {
+            let cuts = 0;
+            for (let i = 0; i < n; i++) {
+                if (!gaps[i].includes(line)) {
+                    cuts++;
+                }
+            }
+            res = Math.min(res, cuts);
+        }
+
+        return res;
+    }
+}
+```
+
+::tabs-end
+
+### Time & Space Complexity
+
+* Time complexity: $O(m * n * g)$
+* Space complexity: $O(n * g)$
+
+> Where $m$ is the sum of widths of the bricks in the first row, $n$ is the number of rows and $g$ is the average number of gaps in each row.
+
+---
+
+## 2. Hash Map
+
+::tabs-start
+
+```python
+class Solution:
+    def leastBricks(self, wall: List[List[int]]) -> int:
+        countGap = {0: 0}
+
+        for r in wall:
+            total = 0
+            for i in range(len(r) - 1):
+                total += r[i]
+                countGap[total] = 1 + countGap.get(total, 0)
+
+        return len(wall) - max(countGap.values())
+```
+
+```java
+public class Solution {
+    public int leastBricks(List<List<Integer>> wall) {
+        HashMap<Integer, Integer> countGap = new HashMap<>();
+        countGap.put(0, 0);
+
+        for (List<Integer> row : wall) {
+            int total = 0;
+            for (int i = 0; i < row.size() - 1; i++) {
+                total += row.get(i);
+                countGap.put(total, countGap.getOrDefault(total, 0) + 1);
+            }
+        }
+
+        int maxGaps = 0;
+        for (int count : countGap.values()) {
+            maxGaps = Math.max(maxGaps, count);
+        }
+
+        return wall.size() - maxGaps;
+    }
+}
+```
+
+```cpp
+class Solution {
+public:
+    int leastBricks(vector<vector<int>>& wall) {
+        unordered_map<int, int> countGap;
+        countGap[0] = 0;
+
+        for (const auto& row : wall) {
+            int total = 0;
+            for (size_t i = 0; i < row.size() - 1; ++i) {
+                total += row[i];
+                countGap[total]++;
+            }
+        }
+
+        int maxGaps = 0;
+        for (const auto& [key, value] : countGap) {
+            maxGaps = max(maxGaps, value);
+        }
+
+        return wall.size() - maxGaps;
+    }
+};
+```
+
+```javascript
+class Solution {
+    /**
+     * @param {number[][]} wall
+     * @return {number}
+     */
+    leastBricks(wall) {
+        const countGap = new Map();
+        countGap.set(0, 0);
+        for (const row of wall) {
+            let total = 0;
+            for (let i = 0; i < row.length - 1; i++) {
+                total += row[i];
+                countGap.set(total, (countGap.get(total) || 0) + 1);
+            }
+        }
+        return wall.length - Math.max(...countGap.values());
+    }
+}
+```
+
+::tabs-end
+
+### Time & Space Complexity
+
+* Time complexity: $O(N)$
+* Space complexity: $O(g)$
+
+> Where $N$ is the total number of bricks in the wall and $g$ is the total number of gaps in all the rows.