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README.md

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|406|[Queue Reconstruction by Height](https://leetcode.com/problems/queue-reconstruction-by-height/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_406.java)| O(nlogn)|O(1) | Medium| LinkedList, PriorityQueue
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|405|[Convert a Number to Hexadecimal](https://leetcode.com/problems/convert-a-number-to-hexadecimal/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_405.java)| O(n)|O(1) | Easy|
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|404|[Sum of Left Leaves](https://leetcode.com/problems/sum-of-left-leaves/)|[Solution](../master/src/main/java/com/fishercoder/solutions/SumofLeftLeaves.java)| O(n)|O(h) | Easy|
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|403|[Frog Jump](https://leetcode.com/problems/frog-jump/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_403.java)| O(n^2)|O(n^2) | Hard| DP
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|402|[Remove K Digits](https://leetcode.com/problems/remove-k-digits/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_402.java)| O(n)|O(n) | Medium| Greedy, Stack
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|401|[Binary Watch](https://leetcode.com/problems/binary-watch/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_401.java)| O(1)|O(1) | Easy|
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|400|[Nth Digit](https://leetcode.com/problems/nth-digit/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_400.java)| O(n)|O(1) | Easy|
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package com.fishercoder.solutions;
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import java.util.HashMap;
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import java.util.HashSet;
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import java.util.Map;
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import java.util.Set;
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/**
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* 403. Frog Jump
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*
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* A frog is crossing a river.
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* The river is divided into x units and at each unit there may or may not exist a stone.
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* The frog can jump on a stone, but it must not jump into the water.
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Given a list of stones' positions (in units) in sorted ascending order,
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determine if the frog is able to cross the river by landing on the last stone.
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Initially, the frog is on the first stone and assume the first jump must be 1 unit.
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If the frog's last jump was k units, then its next jump must be either k - 1, k, or k + 1 units.
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Note that the frog can only jump in the forward direction.
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Note:
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The number of stones is ≥ 2 and is < 1,100.
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Each stone's position will be a non-negative integer < 231.
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The first stone's position is always 0.
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Example 1:
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[0,1,3,5,6,8,12,17]
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There are a total of 8 stones.
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The first stone at the 0th unit, second stone at the 1st unit,
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third stone at the 3rd unit, and so on...
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The last stone at the 17th unit.
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Return true. The frog can jump to the last stone by jumping
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1 unit to the 2nd stone, then 2 units to the 3rd stone, then
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2 units to the 4th stone, then 3 units to the 6th stone,
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4 units to the 7th stone, and 5 units to the 8th stone.
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Example 2:
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[0,1,2,3,4,8,9,11]
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Return false. There is no way to jump to the last stone as
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the gap between the 5th and 6th stone is too large.
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*/
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public class _403 {
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/**Reference: https://discuss.leetcode.com/topic/59903/very-easy-to-understand-java-solution-with-explanations/2
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* and https://leetcode.com/articles/frog-jump/#approach-5-using-dynamic-programmingaccepted*/
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public boolean canCross(int[] stones) {
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if (stones.length == 0) return true;
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Map<Integer, Set<Integer>> map = new HashMap<>(stones.length);
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map.put(0, new HashSet<>());
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map.get(0).add(1);
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for (int i = 1; i < stones.length; i++) {
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map.put(stones[i], new HashSet<>());
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}
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for (int i = 0; i < stones.length; i++) {
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int stone = stones[i];
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for (int step : map.get(stone)) {
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int reach = step + stone;
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if (reach == stones[stones.length-1]) return true;
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Set<Integer> set = map.get(reach);
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if (set != null) {
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set.add(step);
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if (step - 1 > 0) {
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set.add(step - 1);
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}
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set.add(step + 1);
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}
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}
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}
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return false;
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}
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}

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