monoid bialgebra
Let G be a monoid and k a field. Consider the vector space kG over k with basis G. More precisely,
kG={f:G→k|f(g)=0 for almost all g∈G}. |
We identify g∈G with a function fg:G→k such that fg(g)=1 and fg(h)=0 for h≠g. Thus, every element in kG is of the form
∑g∈Gλgg, |
for λg∈k. The vector space kG can be turned into a k-algebra, if we define multiplication as follows:
g⋅h=gh, |
where on the right side we have a multiplication in the monoid G. This definition extends linearly to entire kG and defines an algebra structure on kG, where neutral element of G is the identity
in kG.
Furthermore, we can turn kG into a coalgebra as follows: comultiplication Δ:kG→kG⊗kG is defined by Δ(g)=g⊗g and counit ε:kG→k is defined by ε(g)=1. One can easily check that this defines coalgebra structure on kG.
The vector space kG is a bialgebra with with these algebra and coalgebra structures and it is called a monoid bialgebra.
Title | monoid bialgebra |
---|---|
Canonical name | MonoidBialgebra |
Date of creation | 2013-03-22 18:58:48 |
Last modified on | 2013-03-22 18:58:48 |
Owner | joking (16130) |
Last modified by | joking (16130) |
Numerical id | 4 |
Author | joking (16130) |
Entry type | Example |
Classification | msc 16W30 |