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1880 Rhode Island gubernatorial election

From Wikipedia, the free encyclopedia

1880 Rhode Island gubernatorial election

← 1879 April 7, 1880 1881 →
 
Nominee Alfred H. Littlefield Horace A. Kimball Albert C. Howard
Party Republican Democratic Independent Republican
Popular vote 10,224 7,440 5,047
Percentage 44.82% 32.62% 22.13%

County results
Littlefield:      40–50%      50–60%

Governor before election

Charles C. Van Zandt
Republican

Elected Governor

Alfred H. Littlefield
Republican

The 1880 Rhode Island gubernatorial election was held on April 7, 1880. Republican nominee Alfred H. Littlefield defeated Democratic nominee Horace A. Kimball with 44.82% of the vote.

General election

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Candidates

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Major party candidates

  • Alfred H. Littlefield, Republican
  • Horace A. Kimball, Democratic

Other candidates

Results

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1880 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Alfred H. Littlefield 10,224 44.82%
Democratic Horace A. Kimball 7,440 32.62%
Independent Republican Albert C. Howard 5,047 22.13%
Majority 2,784
Turnout
Republican hold Swing

References

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  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 27, 2020.
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