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Word count #818

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Aug 28, 2019
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22 changes: 22 additions & 0 deletions Others/CountWords.java
Original file line number Diff line number Diff line change
Expand Up @@ -16,6 +16,7 @@ public static void main(String[] args) {
String str = input.nextLine();

System.out.println("Your text has " + wordCount(str) + " word(s)");
System.out.println("Your text has " + secondaryWordCount(str) + " word(s)");
input.close();
}

Expand All @@ -25,4 +26,25 @@ private static int wordCount(String s) {
return s.trim().split("[\\s]+").length;
}

/**
* counts the number of words in a sentence but ignores all potential
* non-alphanumeric characters that do not represent a word. runs in O(n) where
* n is the length of s
*
* @param s String: sentence with word(s)
* @return int: number of words
*/
private static int secondaryWordCount(String s) {
if (s == null || s.isEmpty())
return 0;
StringBuilder sb = new StringBuilder();
for (char c : s.toCharArray()) {
if (Character.isLetter(c) || Character.isDigit(c))
sb.append(c);
}
s = sb.toString();
return s.trim().split("[\\s]+").length;

}

}
25 changes: 25 additions & 0 deletions Others/Palindrome.java
Original file line number Diff line number Diff line change
Expand Up @@ -22,4 +22,29 @@ public boolean SecondWay(String x) {

return SecondWay(x.substring(1, x.length() - 1));
}

/**
* This method ignores all non-alphanumeric characters and case runs in O(n)
* where n is the length of s
*
* @param s String to check
* @return true if s is palindrome else false
*/
public boolean isPalindrome(String s) {
s = s.toLowerCase().trim();
StringBuilder sb = new StringBuilder();
for (char c : s.toCharArray()) {
if (Character.isLetter(c) || Character.isDigit(c))
sb.append(c);
}
s = sb.toString();
int start = 0;
int end = s.length() - 1;
while (start <= end) {
if (s.charAt(start++) != s.charAt(end--))
return false;

}
return true;
}
}
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