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Week3 homework #14

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b7d9e3d
Testing
jshortz Jun 8, 2019
d645b0e
Removing test.txt
jshortz Jun 8, 2019
79955f3
JS lists working (but ugly)
jshortz Jun 9, 2019
9c081d8
Homework sort of finished. Can't get images to display. Looks horribl…
jshortz Jun 11, 2019
6756a96
Notes Update, JavaScript practice
jshortz Jun 29, 2019
5542b97
Redoing Homework
jshortz Jun 29, 2019
66c1b93
Recreating homework
jshortz Jun 29, 2019
cae0024
finished 2.1 and 2.1
jshortz Jul 13, 2019
d67d07e
finished 2.3
jshortz Jul 13, 2019
8098ebc
finished 2.4 and 2.5
jshortz Jul 13, 2019
9e84302
finished 2.6
jshortz Jul 13, 2019
cc6b2f9
finished 2.7
jshortz Jul 13, 2019
8673c7b
finished 3 (no bonus)
jshortz Jul 13, 2019
a180a51
bonus homework finished
jshortz Jul 13, 2019
c2ad5fa
fixed issues from unit tests (still failing 2-2)
jshortz Jul 13, 2019
327c203
fixed function call in 2.2, all unit tests pass
jshortz Jul 14, 2019
b03dfbb
Removing Notes. Again. Always.
jshortz Jul 14, 2019
3a47521
Update Week3/homework/step2-2.js
jshortz Jul 28, 2019
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finished 2.7
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@jshortz
jshortz committed Jul 13, 2019
commit cc6b2f9456687c571649dd7e65f66f729e27ad3c
6 changes: 5 additions & 1 deletion Week3/homework/step2-7.js
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Expand Up @@ -20,4 +20,8 @@ f2(y);

console.log(y);

// Add your explanation as a comment here
/* In the x-code, we are logging the value of x, which has not changed. If we want this code to return 10,
we need to console.log(f1(x)). In the y-code, y is an object. The properties of an object can be altered this way,
so the function changes the value of x to 10. No alteration has been done to the variable reference itself. If f2
attempted to change the *value* of y (rather than an attribute of its object), it would yield results like the x-code.
For example, if the function is altered, val = { x: 10 }; return val;, it will return { x: 9 } */
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I think you get it (?). Another example:

let a = 4
let b = a
a += 1
What's the value of b?

vs objects...

let a = { name: 'gabe' }
b = a
a.country = 'us'
what's the value of b?

Do you see the difference?

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Yep - I assume it has to do with how JS stores them in memory - when b is set to an object, it's a reference to that object, not a new object with the same details. So whenever a property of 'a' changes, 'b' will 'change' as well (because they're both just pointing to the same object). But when a = 4 and b = a, it's setting b equal to a value of 4 (not pointing to an object). So changing the value of 'a' after that doesn't change the value of 'b'.

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So in the objects example, both a and b would have a value of

{
name: 'gabe',
country: 'us'
}

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