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Jul 12, 2022
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23 changes: 15 additions & 8 deletions 105-Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.py
Original file line number Diff line number Diff line change
@@ -1,10 +1,17 @@
class Solution:
def buildTree(self, preorder: List[int], inorder: List[int]) -> Optional[TreeNode]:
if not preorder or not inorder:
return None

root = TreeNode(preorder[0])
mid = inorder.index(preorder[0])
root.left = self.buildTree(preorder[1:mid + 1], inorder[:mid])
root.right = self.buildTree(preorder[mid + 1:], inorder[mid + 1:])
return root
inorder_index_mapping = {}
for k,v in enumerate(inorder):
inorder_index_mapping[v] = k
index = 0
def buildtree(left,right):
nonlocal index
if left>right:
return None
root_val=preorder[index]
root = TreeNode(root_val)
index+=1
root.left = buildtree(left, inorder_index_mapping[root_val]-1)
root.right = buildtree(inorder_index_mapping[root_val]+1, right)
return root
return buildtree(0, len(preorder)-1)
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