Unused param is not available in 3.11

python · erlend-aasland · Jul 3, 2023 · Jul 3, 2023 · Jul 3, 2023 · Jul 3, 2023
commit b0621092d725ca70db5b69a88234f1395e1c5633
diff --git a/Lib/test/test_clinic.py b/Lib/test/test_clinic.py
@@ -885,44 +885,6 @@ def test_defining_class_param_cannot_be_optional(self):
         out = self.parse_function_should_fail(block)
         self.assertEqual(out, expected_error_msg)
 
-    def test_unused_param(self):
-        block = self.parse("""
-            module foo
-            foo.func
-                fn: object
-                k: float
-                i: float(unused=True)
-                /
-                *
-                flag: bool(unused=True) = False
-        """)
-        sig = block.signatures[1]  # Function index == 1
-        params = sig.parameters
-        conv = lambda fn: params[fn].converter
-        dataset = (
-            {"name": "fn", "unused": False},
-            {"name": "k", "unused": False},
-            {"name": "i", "unused": True},
-            {"name": "flag", "unused": True},
-        )
-        for param in dataset:
-            name, unused = param.values()
-            with self.subTest(name=name, unused=unused):
-                p = conv(name)
-                # Verify that the unused flag is parsed correctly.
-                self.assertEqual(unused, p.unused)
-
-                # Now, check that we'll produce correct code.
-                decl = p.simple_declaration(in_parser=False)
-                if unused:
-                    self.assertIn("Py_UNUSED", decl)
-                else:
-                    self.assertNotIn("Py_UNUSED", decl)
-
-                # Make sure the Py_UNUSED macro is not used in the parser body.
-                parser_decl = p.simple_declaration(in_parser=True)
-                self.assertNotIn("Py_UNUSED", parser_decl)
-
     def parse(self, text):
         c = FakeClinic()
         parser = DSLParser(c)