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[Form] Fix debug form when using partial type name #30509

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Merged
merged 1 commit into from
Mar 13, 2019
Merged

[Form] Fix debug form when using partial type name #30509

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2 changes: 1 addition & 1 deletion src/Symfony/Component/Form/Command/DebugCommand.php
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Original file line number Diff line number Diff line change
Expand Up @@ -115,7 +115,7 @@ protected function execute(InputInterface $input, OutputInterface $output)
sort($options[$k]);
}
} else {
if (!class_exists($class)) {
if (!class_exists($class) || !is_subclass_of($class, FormTypeInterface::class)) {
$class = $this->getFqcnTypeClass($input, $io, $class);
}
$resolvedType = $this->formRegistry->getType($class);
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9 changes: 9 additions & 0 deletions src/Symfony/Component/Form/Tests/Command/DebugCommandTest.php
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Original file line number Diff line number Diff line change
Expand Up @@ -66,6 +66,15 @@ public function testDebugSingleFormType()
$this->assertContains('Symfony\Component\Form\Extension\Core\Type\FormType (Block prefix: "form")', $tester->getDisplay());
}

public function testDebugDateTimeType()
{
$tester = $this->createCommandTester();
$tester->execute(['class' => 'DateTime'], ['decorated' => false, 'interactive' => false]);

$this->assertEquals(0, $tester->getStatusCode(), 'Returns 0 in case of success');
$this->assertContains('Symfony\Component\Form\Extension\Core\Type\DateTimeType (Block prefix: "datetime")', $tester->getDisplay());
}

public function testDebugFormTypeOption()
{
$tester = $this->createCommandTester();
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